Question
In the circuit $$P \ne R$$ the reading of the galvanometer is same with switch $$S$$ open or closed. Then
In the circuit $$P \ne R$$ the reading of the galvanometer is same with switch $$S$$ open or closed. Then
A.
$${I_R} = {I_G}$$
B.
$${I_P} = {I_G}$$
C.
$${I_Q} = {I_G}$$
D.
$${I_Q} = {I_R}$$
Answer :
$${I_R} = {I_G}$$
Solution :
Since the opening or closing the switch does not affect the current through $$G,$$ it means that in both the cases there is no current passing through $$S.$$ Thus potential at $$A$$ is equal to potential at $$B$$ and it is the case of balanced wheatstone bridge..
$${I_P} = {I_Q}$$ and $${I_R} = {I_G}$$
Since the opening or closing the switch does not affect the current through $$G,$$ it means that in both the cases there is no current passing through $$S.$$ Thus potential at $$A$$ is equal to potential at $$B$$ and it is the case of balanced wheatstone bridge..
$${I_P} = {I_Q}$$ and $${I_R} = {I_G}$$
