If we consider that $$\frac{1}{6},$$ in place of $$\frac{1}{{12}},$$ mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of the substance will

Solution :
$$\eqalign{ & {\text{Relative atomic mass}} \cr & {\text{ = }}\frac{{{\text{Mass of one atom of the element}}}}{{{{\frac{1}{{12}}}^{th}}\,{\text{part of the mass of one atom of Carbon}}\, - 12}} \cr & {\text{or}}\,\,\frac{{{\text{Mass of one atom of the element}}}}{{{\text{mass of one atom of the}}\,C - 12}} \times 12 \cr & {\text{Now if we use}}\,\,\frac{1}{6}\,\,{\text{in place of}}\,\,\frac{1}{{12}}\,\,{\text{the formula becomes}} \cr & {\text{Relative atomic mass}} = \frac{{{\text{Mass of one atom of element}}}}{{{\text{Mass of one atom of carbon}}}} \times 6 \cr & \therefore \,{\text{Relative atomic mass decrease twice}}{\text{.}} \cr} $$