Question

If the system of equations
$$\eqalign{ & ax + by + c = 0 \cr & bx + cy + a = 0 \cr & cx + ay + b = 0 \cr} $$
has a solution then the system of equations
$$\eqalign{ & \left( {b + c} \right)x + \left( {c + a} \right)y + \left( {a + b} \right)z = 0 \cr & \left( {c + a} \right)x + \left( {a + b} \right)y + \left( {b + c} \right)z = 0 \cr & \left( {a + b} \right)x + \left( {b + c} \right)y + \left( {c + a} \right)z = 0 \cr} $$
has

A. only one solution
B. no solution
C. infinite number of solutions  
D. None of these
Answer :   infinite number of solutions
Solution :
For existence of a solution of the first system,
\[\left| {\begin{array}{*{20}{c}} a&b&c \\ b&c&a \\ c&a&b \end{array}} \right| = 0.\]
The second system will have a nontrivial solution if we can prove that
\[\left| {\begin{array}{*{20}{c}} {b + c}&{c + a}&{a + b} \\ {c + a}&{a + b}&{b + c} \\ {a + b}&{b + c}&{c + a} \end{array}} \right| = 0.\]
Establish \[\left| {\begin{array}{*{20}{c}} {b + c}&{c + a}&{a + b} \\ {c + a}&{a + b}&{b + c} \\ {a + b}&{b + c}&{c + a} \end{array}} \right| = 2\left| {\begin{array}{*{20}{c}} a&b&c \\ b&c&a \\ c&a&b \end{array}} \right| = 0.\]
Remember that the existence of one nontrivial solution implies existence of infinite number of non-trivial solutions

Releted MCQ Question on
Algebra >> Matrices and Determinants

Releted Question 1

Consider the set $$A$$ of all determinants of order 3 with entries 0 or 1 only. Let $$B$$  be the subset of $$A$$ consisting of all determinants with value 1. Let $$C$$  be the subset of $$A$$ consisting of all determinants with value $$- 1.$$ Then

A. $$C$$ is empty
B. $$B$$  has as many elements as $$C$$
C. $$A = B \cup C$$
D. $$B$$  has twice as many elements as elements as $$C$$
Releted Question 2

If $$\omega \left( { \ne 1} \right)$$  is a cube root of unity, then
\[\left| {\begin{array}{*{20}{c}} 1&{1 + i + {\omega ^2}}&{{\omega ^2}}\\ {1 - i}&{ - 1}&{{\omega ^2} - 1}\\ { - i}&{ - i + \omega - 1}&{ - 1} \end{array}} \right|=\]

A. 0
B. 1
C. $$i$$
D. $$\omega $$
Releted Question 3

Let $$a, b, c$$  be the real numbers. Then following system of equations in $$x, y$$  and $$z$$
$$\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} - \frac{{{z^2}}}{{{c^2}}} = 1,$$    $$\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} + \frac{{{z^2}}}{{{c^2}}} = 1,$$    $$ - \frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} + \frac{{{z^2}}}{{{c^2}}} = 1$$     has

A. no solution
B. unique solution
C. infinitely many solutions
D. finitely many solutions
Releted Question 4

If $$A$$ and $$B$$ are square matrices of equal degree, then which one is correct among the followings?

A. $$A + B = B + A$$
B. $$A + B = A - B$$
C. $$A - B = B - A$$
D. $$AB=BA$$

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Matrices and Determinants


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