If the nitrogen atom has electronic configuration $$1{s^7},$$ it would have energy lower than that of the normal ground state configuration $$1{s^2}2{s^2}2{p^3},$$ because the electrons would be closer to the nucleus. Yet $$1{s^7}$$ is not observed because it
violates.
A.
Heisenberg uncertainty principle
B.
Hund's rule
C.
Pauli exclusion principle
D.
Bohr postulate of stationary orbits
Answer :
Pauli exclusion principle
Solution :
As per Pauli Exclusion Principle "no two electrons in the same atom can have all the four quantum numbers equal or an orbital cannot contain more than two electrons and it can accommodate two electrons only when their directions of spins are opposite".
Releted MCQ Question on Physical Chemistry >> Atomic Structure
Releted Question 1
The number of neutrons in dipositive zinc ion with mass number 70 is