Question
If the dimensions of a physical quantity are given by $${M^a}{L^b}{T^c},$$ then the physical quantity will be
A.
velocity if $$a = 1,b = 0,c = - 1$$
B.
acceleration if $$a = 1,b = 1,c = - 2$$
C.
force if $$a = 0,b = - 1,c = - 2$$
D.
pressure if $$a = 1,b = - 1,c = - 2$$
Answer :
pressure if $$a = 1,b = - 1,c = - 2$$
Solution :
Pressure $$ = \frac{{ML{T^{ - 2}}}}{{{L^2}}} = \left[ {M{L^{ - 1}}{T^{ - 2}}} \right]$$
$$ \Rightarrow a = 1,b = - 1,c = - 2.$$