If $$KMn{O_4}$$ is reduced by oxalic acid in an acidic medium then oxidation number of $$Mn$$ changes from
A.
4 to 2
B.
6 to 4
C.
+7 to +2
D.
7 to 4
Answer :
+7 to +2
Solution :
In acid medium
$$MnO_4^ - + 8{H^ + } + 5{e^ - } \to M{n^{2 + }} + 4{H_2}O$$
( $$O.S.$$ of $$Mn$$ changes form +7 to +2 ).
Releted MCQ Question on Inorganic Chemistry >> D and F Block Elements
Releted Question 1
When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volume of hydrogen evolved is