If $${K_1}$$ and $${K_2}$$ are respective equilibrium constants for the two reactions
$$Xe{F_6}\left( g \right) + {H_2}O\left( g \right) \rightleftharpoons $$ $$XeO{F_4}\left( g \right) + 2HF\left( g \right)$$
$$Xe{O_4}\left( g \right) + Xe{F_6}\left( g \right) \rightleftharpoons $$ $$XeO{F_4}\left( g \right) + Xe{O_3}{F_2}\left( g \right)$$
the equilibrium constant for the reaction
$$Xe{O_4}\left( g \right) + 2HF\left( g \right) \rightleftharpoons $$ $$Xe{O_3}{F_2}\left( g \right) + {H_2}O\left( g \right)$$ will be
Releted MCQ Question on Physical Chemistry >> Chemical Equilibrium
Releted Question 1
For the reaction : $${H_2}\left( g \right) + {I_2}\left( g \right) \rightleftharpoons 2HI\left( g \right)$$ the equilibrium constant $${K_p}$$ changes with