Question
If a particle takes $$0.5\,\sec$$ to reach position of minimum velocity from previous such position, then
A.
$$T = 6\,\sec ,\,v = \frac{1}{6}\,Hz$$
B.
$$T = 2\,\sec ,\,v = 1\,Hz$$
C.
$$T = 3\,\sec ,\,v = 3\,Hz$$
D.
$$T = 1\,\sec ,\,v = 1\,Hz$$
Answer :
$$T = 1\,\sec ,\,v = 1\,Hz$$
Solution :
$$\eqalign{
& \frac{T}{2} = 0.5\,\sec \Rightarrow T = 1\,\sec \cr
& v = \frac{1}{T} = 1\,Hz \cr} $$