Question
If $$4\,moles$$ of an ideal gas at $$300\,K$$ occupy volume of $$89.6\,L,$$ then pressure of the gas will be
A.
$$2\,atm$$
B.
$$1\,atm$$
C.
$$1.099\,atm$$
D.
$$2.910\,atm$$
Answer :
$$1.099\,atm$$
Solution :
$$\eqalign{
& PV = nRT \cr
& \Rightarrow P = \frac{{4 \times 0.0821 \times 300}}{{89.6}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\, = 1.099\,atm \cr} $$