Question
Identify $$X$$ and $$Y$$ in the reaction.
\[C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,
\end{smallmatrix}}{\mathop{-CH-}}\,CON{{H}_{2}}\xrightarrow{\frac{B{{r}_{2}}}{NaOH}}\] \[X\xrightarrow{HN{{O}_{2}}}Y\]
A.
\[X=C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,C{{H}_{2}}N{{H}_{2}};\] \[Y=C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,C{{H}_{2}}-OH\]
B.
$$X = C{H_3}CH = CHN{H_2};$$ $$Y = C{H_3}CH = CHOH$$
C.
\[X=C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,N{{H}_{2}};\] \[Y=C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,OH\]
D.
$$X = C{H_3}C{H_2}C{H_2}N{H_2};$$ $$Y = C{H_3}C{H_2}C{H_2}OH$$
Answer :
\[X=C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,N{{H}_{2}};\] \[Y=C{{H}_{3}}\underset{\begin{smallmatrix}
|\,\,\,\,\, \\
C{{H}_{3}}\,\,
\end{smallmatrix}}{\mathop{-CH-}}\,OH\]
Solution :