Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4. Then the number of spectral lines in the emission spectra will be :
A.
2
B.
3
C.
5
D.
6
Answer :
6
Solution :
The possible number of the spectral lines is given
$$ = \frac{{n\left( {n - 1} \right)}}{2} = \frac{{4\left( {4 - 1} \right)}}{2} = 6$$
Releted MCQ Question on Modern Physics >> Atoms And Nuclei
Releted Question 1
If elements with principal quantum number $$n > 4$$ were not allowed in nature, the number of possible elements would be
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