How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions?

Solution :
$$X - X - X - X - X.$$    The four digits 3, 3, 5, 5 can be arranged at $$(-)$$ places in $$\frac{{4!}}{{2!2!}} = 6\,\,{\text{ways}}{\text{.}}$$
The five digits 2, 2, 8, 8, 8 can be arranged at $$(X)$$ places in $$\frac{{5!}}{{2!3!}} = 10\,\,{\text{ways}}{\text{.}}$$
Total no. of arrangements $${\text{ = }}\,{\text{6}} \times {\text{10}}\,{\text{ = }}\,{\text{60}}\,\,{\text{ways}}{\text{.}}$$