Question
Glucose - $$D$$ has a great tendency to be converted into cyclic isomer. Which two carbon atoms get joined through $$'O'$$ to form this hemiacetal ?
A.
$${C_1}\,\,{\text{and}}\,\,{C_4}$$
B.
$${C_1}\,\,{\text{and}}\,\,{C_5}$$
C.
$${C_1}\,\,{\text{and}}\,\,{C_6}$$
D.
$${C_2}\,\,{\text{and}}\,\,{C_6}$$
Answer :
$${C_1}\,\,{\text{and}}\,\,{C_5}$$
Solution :
Glucose exists as glucopyranose ( a six membered ring structure ) which is formed through $${C_1}\,\,{\text{and}}\,\,{C_5}.$$