Question
Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.
| Gases |
$${H_2}$$ |
$$He$$ |
$${O_2}$$ |
$${N_2}$$ |
| Critical temperature in kelvin |
33.2 |
5.3 |
154.3 |
126 |
From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first.
A.
$${H_2},He,{O_2},{N_2}$$
B.
$$He,{O_2},{H_2},{N_2}$$
C.
$${N_2},{O_2},He,{H_2}$$
D.
$${O_2},{N_2},{H_2},He$$
Answer :
$${O_2},{N_2},{H_2},He$$
Solution :
The higher the critical temperature more is the ease with which the gas liquefies. Hence oxygen will liquefy first. The correct order of liquefying the gases will be $${O_2},{N_2},{H_2},He$$