Question
Fig shown below represents an area $$A = 0.5\,{m^2}$$ situated in a uniform magnetic field $$B = 2.0\,{\text{weber}}/{m^2}$$ and making an angle of $${60^ \circ }$$ with respect to magnetic field.
Fig shown below represents an area $$A = 0.5\,{m^2}$$ situated in a uniform magnetic field $$B = 2.0\,{\text{weber}}/{m^2}$$ and making an angle of $${60^ \circ }$$ with respect to magnetic field.
The value of the magnetic flux through the area would be equal to
A.
$$2.0\,{\text{weber}}$$
B.
$$\sqrt 3 \,{\text{weber}}$$
C.
$$\frac{{\sqrt 3 }}{2}\,{\text{weber}}$$
D.
$$0.5\,{\text{weber}}$$
Answer :
$$0.5\,{\text{weber}}$$
Solution :
$$\eqalign{ & \phi = BA\cos \theta = 2.0 \times 0.5 \times \cos {60^ \circ } \cr & = \frac{{2.0 \times 0.5}}{2} \cr & = 0.5\,{\text{weber}}{\text{.}} \cr} $$
$$\eqalign{ & \phi = BA\cos \theta = 2.0 \times 0.5 \times \cos {60^ \circ } \cr & = \frac{{2.0 \times 0.5}}{2} \cr & = 0.5\,{\text{weber}}{\text{.}} \cr} $$
