Question
Distance travelled by a particle at any instant $$'t'$$ can be represented as $$S = A\left( {t + B} \right) + C{t^2}.$$ The dimensions of $$B$$ are
A.
$$\left[ {{M^0}{L^1}{T^{ - 1}}} \right]$$
B.
$$\left[ {{M^0}{L^0}{T^1}} \right]$$
C.
$$\left[ {{M^0}{L^{ - 1}}{T^{ - 2}}} \right]$$
D.
$$\left[ {{M^0}{L^2}{T^{ - 2}}} \right]$$
Answer :
$$\left[ {{M^0}{L^0}{T^1}} \right]$$
Solution :
In $$S = A\left( {t + B} \right) + C{t^2};B$$ is added to time $$t.$$
Therefore, dimensions of $$B$$ are those of time.