Dimension of $$\frac{1}{{{\mu _0}{\varepsilon _0}}},$$ where symbols have their usual meaning, are-
A.
$$\left[ {{L^{ - 1}}T} \right]$$
B.
$$\left[ {{L^{ - 2}}{T^2}} \right]$$
C.
$$\left[ {{L^2}{T^{ - 2}}} \right]$$
D.
$$\left[ {L{T^{ - 1}}} \right]$$
Answer :
$$\left[ {{L^2}{T^{ - 2}}} \right]$$
Solution :
we know that the velocity of light in vacuum is given by
$$\eqalign{
& c = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }} \cr
& \therefore \frac{1}{{{\mu _0}{\varepsilon _0}}} = {c^2} = {L^2}{T^{ - 2}} \cr} $$
Releted MCQ Question on Basic Physics >> Unit and Measurement
Releted Question 1
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