Considering the state of hybridisation of carbon atoms, find out the molecule among the following which is linear?
A.
$$C{H_3} - C \equiv C - C{H_3}$$
B.
$$C{H_2} = CH - C{H_2} - C \equiv CH$$
C.
$$C{H_3} - C{H_2} - C{H_2} - C{H_3}$$
D.
$$C{H_3} - C = CH - C{H_3}$$
Answer :
$$C{H_3} - C \equiv C - C{H_3}$$
Solution :
$${H_3}\mathop C\limits^4 - \mathop C\limits^3 \equiv \mathop C\limits^2 - \mathop C\limits^1 {H_3}$$ is linear because $${C_2}$$ and $${C_3}$$ are $$sp$$ hybridised carbon atom.
Releted MCQ Question on Inorganic Chemistry >> Chemical Bonding and Molecular Structure
Releted Question 1
The compound which contains both ionic and covalent bonds is