Question

Consider the following statements
$$p :$$ A tumbler is half empty.
$$q :$$ A tumbler is half full.
Then, the combination form of “$$p$$ if and only if $$q\,$$” is

A. a tumbler is half empty and half full
B. a tumbler is half empty if and only if it is half full  
C. Both $$\left( A \right){\text{ and }}\left( B \right)$$
D. None of the above
Answer :   a tumbler is half empty if and only if it is half full
Solution :
The given statements are
$$p :\,$$ A tumbler is half empty.
$$q :\,$$ A tumbler is half full.
We know that, if the first statement happens, then the second happens and also if the second happens, then the first happens. We can express this fact as
If a tumbler is half empty, then it is half full.
If a tumbler is half full, then it is half empty.
We combine these two statements and get the following. A tumbler is half empty, if and only if it is half full.

Releted MCQ Question on
Algebra >> Mathematical Reasoning

Releted Question 1

Let $$p$$ be the statement “$$x$$ is an irrational number”, $$q$$ be the statement “$$y$$ is a transcendental number”, and $$r$$ be the statement “$$x$$ is a rational number if $$f y$$  is a transcendental number”.
Statement - 1 : $$r$$ is equivalent to either $$q$$ or $$p$$
Statement - 2 : $$r$$ is equivalent to $$ \sim \left( {p \leftrightarrow \sim q} \right).$$

A. Statement - 1 is false, Statement - 2 is true
B. Statement - 1 is true, Statement - 2 is true ; Statement - 2 is a correct explanation for Statement - 1
C. Statement - 1 is true, Statement - 2 is true ; Statement - 2 is not a correct explanation for Statement - 1
D. none of these
Releted Question 2

The statement $$p \to \left( {q \to p} \right)$$   is equivalent to

A. $$p \to \left( {p \to q} \right)$$
B. $$p \to \left( {p \vee q} \right)$$
C. $$p \to \left( {p \wedge q} \right)$$
D. $$p \to \left( {p \leftrightarrow q} \right)$$
Releted Question 3

Statement - 1 : $$ \sim \left( {p \leftrightarrow \sim q} \right)$$   is equivalent to $${p \leftrightarrow q}.$$
Statement - 2 : $$ \sim \left( {p \leftrightarrow \sim q} \right)$$   is a tautology

A. Statement - 1 is true, Statement - 2 is true; Statement - 2 is not a correct explanation for Statement - 1.
B. Statement - 1 is true, Statement - 2 is false.
C. Statement - 1 is false, Statement - 2 is true.
D. Statement - 1 is true, Statement - 2 is true, Statement - 2 is a correct explanation for statement - 1
Releted Question 4

Consider the following statements
$$P$$ : Suman is brilliant
$$Q$$ : Suman is rich
$$R$$ : Suman is honest
The negation of the statement “Suman is brilliant and dishonest if and only if Suman is rich” can be expressed as

A. $$ \sim \left( {Q \leftrightarrow \left( {P \wedge \sim R} \right)} \right)$$
B. $$ \sim Q \leftrightarrow \sim P \wedge R$$
C. $$ \sim \left( {P \wedge \sim R} \right) \leftrightarrow Q$$
D. $$ \sim P \wedge \left( {Q \leftrightarrow \sim R} \right)$$

Practice More Releted MCQ Question on
Mathematical Reasoning


Practice More MCQ Question on Maths Section