111.
A piston filled with $$0.04\,mol$$ of an ideal gas expands reversibly from $$50.0\,mL$$ to $$375\,mL$$ at a constant temperature of $${37.0^ \circ }C.$$ As it does so, it absorbs $$208\,J$$ of heat. The values of $$q$$ and $$w$$ for the process will be :
$$\left( {R = 8.314\,J/mol\,K} \right)\left( {ln\,7.5 = 2.01} \right)$$
Process is isothermal reversible expansion, hence
$$\eqalign{
& \Delta U = 0,{\text{therefore}}\,\,q = - w. \cr
& {\text{Since}}\,\,q = + 208\,J,\,W = - 208\,J \cr} $$
112.
The enthalpies of combustion of carbon and carbon monoxide are $$- 393.5$$ and $$ - 283\,kJ\,mo{l^{ - 1}}$$ respectively. The enthalpy of formation of carbon monoxide per mole is
$$\Delta G = - ve\,{\text{means the process is spontaneous}}{\text{.}}$$
114.
$${\text{The}}\,\Delta H_f^0\,{\text{for}}\,C{O_2}\left( g \right),\,CO\left( g \right)\,$$ and $${H_2}O\left( g \right)$$ are $$-393.5,$$ $$-110.5$$ and $$ - 241.8\,kJ\,mo{l^{ - 1}}$$ respectively. The standard enthalpy change ( in $$kJ$$ ) for the reaction $$C{O_2}\left( g \right) + {H_2}\left( g \right) \to CO\left( g \right) + {H_2}O\left( g \right)\,{\text{is}}$$
Thermodynamicsis not concerned about how and at what rate chemical reactions are carried out, but is based on initial and final states of a system undergoing the change
117.
The change in energy on freezing $$1.0\,kg$$ of liquid water at $${0^ \circ }C$$ and $$atm$$ is ( Given energy of 1 fusion of ice $$ = 6.03\,kJ\,mo{l^{ - 1}}$$ at $${0^ \circ }C$$ )
Enthalpy of freezing of water $$ = - 6.03\,kJ\,mo{l^{ - 1}}$$ at $${0^ \circ }C$$ i.e., Enthalpy change on freezing of 18$$\,g$$ of water at $${0^ \circ }C = - 6.03\,kJ$$
∴ Enthalpy change on freezing 1000$$\,g$$ of water $$ = - \frac{{6.03}}{{18}} \times 1000 = - 335\,kJ$$
118.
The heat of atomization of methane and ethane are $$360\,kJ/mol$$ and $$620\,kJ/mol,$$ respectively. The longest wavelength of light capable of breaking the $$C – C$$ bond is ( Avogadro number $$ = 6.02 \times {10^{23}}mo{l^{ - 1}},h = 6.62 \times {10^{ - 34}}J\,\left. s \right):$$
119.
$$\left( {\Delta H - \Delta U} \right)$$ for the formation of carbon monoxide $$(CO)$$ from its elements at $$298 K$$ is
$$\left( {R = 8.314\,J{K^{ - 1}}\,mo{l^{ - 1}}} \right)$$
For the reaction,
$$\eqalign{
& {C_{\left( s \right)}} + \frac{1}{2}{O_{2\left( g \right)}} \to CO \cr
& \Delta H = \Delta U + \Delta nRT\,\,or\,\,\Delta H - \Delta U = \Delta nRT \cr
& \Delta n = 1 - \frac{1}{2} = \frac{1}{2}; \cr
& \Delta H - \Delta U = \frac{1}{2} \times 8.314 \times 298 \cr
& = 1238.78\,J\,mo{l^{ - 1}} \cr} $$
120.
For a reaction, $$P + Q \to R + S.$$ The value of $$\Delta {H^ \circ }$$ is $$ - 30\,kJ\,mo{l^{ - 1}}$$ and $$\Delta S$$ is $$ - 100\,J\,{K^{ - 1}}\,mo{l^{ - 1}}.$$ At what temperature the reaction will be at equilibrium ?