71.
An $$ion$$ has 18 electrons in the outermost shell, it is
A
$$C{u^ + }$$
B
$$T{h^{4 + }}$$
C
$$C{s^ + }$$
D
$${K^ + }$$
Answer :
$$C{u^ + }$$
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The electronic configuration of $$Cu,Th,Cs$$ and $$K$$ are
$$\eqalign{
& {\text{Cu}}\left( {29} \right) = 2,8,18,1 \cr
& C{u^ + } = 2,8,18 \cr
& Th\left( {90} \right) = 2,8,18,32,18,10,2 \cr
& T{h^{4 + }} = 2,8,18,32,18,8 \cr
& Cs\left( {55} \right) = 2,8,18,18,8,1 \cr
& C{s^ + } = 2,8,18,18,8 \cr
& K\left( {19} \right) = 2,8,8,1 \cr
& {K^ + } = 2,8,8 \cr} $$
Thus, $$C{u^ + }$$ has 18 electrons in the outermost shell.
72.
The number of electrons which will together weigh one gram is
A
$$1.098 \times {10^{27}}\,{\text{electrons}}$$
B
$$9.1096 \times {10^{31}}\,{\text{electrons}}$$
C
$${\text{1}}\,\,{\text{electron}}$$
D
$$1 \times {10^4}\,{\text{electrons}}$$
Answer :
$$1.098 \times {10^{27}}\,{\text{electrons}}$$
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$$\eqalign{
& {\text{Mass of an electron}} = 9.1096 \times {10^{ - 31}}\,kg \cr
& 1\,g\,\,{\text{or}}\,\,{10^{ - 3}}\,kg = \frac{1}{{9.1096 \times {{10}^{ - 31}}}} \times {10^{ - 3}} \cr
& = 1.098 \times {10^{27}}\,{\text{electrons}} \cr} $$
73.
Which of the following configurations does not follow Hund's rule of maximum multiplicity ?
A
$$1{s^2}2{s^2}2{p^6}3{s^2}3{p^2}$$
B
$$1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^2}3{d^6}$$
C
$$1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}4{s^1}3{d^5}$$
D
$$1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^4}4{s^2}$$
Answer :
$$1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^4}4{s^2}$$
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The configuration does not follow Hund's rule of maximum multiplicity.
74.
Maximum number of electrons in a subshell of an atom is determined by the following
A
$$4l + 2$$
B
$$2l + 1$$
C
$$4l - 2$$
D
$$2{n^2}$$
Answer :
$$4l + 2$$
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Discuss Question
Total number of subshells $$ = \left( {2l + 1} \right)$$
∴ Maximum number of electrons in the subshell
$$\eqalign{
& = 2\left( {2l + 1} \right) \cr
& = 4l + 2 \cr} $$
75.
The de Broglie wavelength of a car of mass $$1000\,kg$$ and velocity $$36\,km/hr$$ is :
A
$$6.626 \times {10^{ - 34}}m$$
B
$$6.626 \times {10^{ - 38}}m$$
C
$$6.626 \times {10^{ - 31}}m$$
D
$$6.626 \times {10^{ - 30}}m$$
Answer :
$$6.626 \times {10^{ - 38}}m$$
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$$\eqalign{
& \lambda = \frac{h}{{mv}} \cr
& h = 6.6 \times {10^{ - 34}}J{\text{ - }}s \cr
& m = 1000\,kg \cr
& v = 36\,km/hr = \frac{{36 \times {{10}^3}}}{{60 \times 60}}m/\sec = 10\,m/\sec \cr
& \therefore \,\,\lambda = \frac{{6.6 \times {{10}^{ - 34}}}}{{{{10}^3} \times 10}} = 6.6 \times {10^{ - 38}}m \cr} $$
76.
Which one of the following set of quantum numbers is not possible for $$4p$$ electron?
A
$$n = 4,l = 1,m = - 1,{m_s} = + \frac{1}{2}$$
B
$$n = 4,l = 1,m = 0,{m_s} = + \frac{1}{2}$$
C
$$n = 4,l = 1,m = 2,{m_s} = + \frac{1}{2}$$
D
$$n = 4,l = 1,m = - 1,{m_s} = - \frac{1}{2}$$
Answer :
$$n = 4,l = 1,m = 2,{m_s} = + \frac{1}{2}$$
View Solution
Discuss Question
$${\text{For }}4p{\text{ electron}}\,n = 4,l = 1,$$ $$m = - 1,0 + 1\,{\text{and}}\,s = + \frac{1}{2}\,{\text{or}}\, - \frac{1}{2}$$
77.
Compare the energies of two radiations $${E_1}$$ with wavelength $$800\,nm$$ and $${E_2}$$ with wavelength $$400\,nm.$$
A
$${E_1} = 2{E_2}$$
B
$${E_1} = {E_2}$$
C
$${E_2} = 2{E_1}$$
D
$${E_2} = - \frac{1}{2}{E_1}$$
Answer :
$${E_2} = 2{E_1}$$
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$${E_1} = \frac{{hc}}{{{\lambda _1}}},{E_2} = \frac{{hc}}{{{\lambda _2}}}$$
$$\frac{{{E_1}}}{{{E_2}}} = \frac{{hc}}{{{\lambda _1}}} \times \frac{{{\lambda _2}}}{{hc}}$$ $${\text{or}}\,\,\,\frac{{{E_1}}}{{{E_2}}} = \frac{{{\lambda _2}}}{{{\lambda _1}}} = \frac{{400}}{{800}};\frac{{{E_1}}}{{{E_2}}} = \frac{1}{2}$$ $${\text{or}}\,\,\,{E_2} = 2{E_1}$$
78.
In a multi-electron atom, which of the following orbitals described by the three quantum members will have the same energy in the absence of magnetic and electric fields?
$$\eqalign{
& \left( {\text{A}} \right)n = 1,l = 0,m = 0 \cr
& \left( {\text{B}} \right)n = 2,l = 0,m = 0 \cr
& \left( {\text{C}} \right)n = 2,l = 1,m = 1 \cr
& \left( {\text{D}} \right)n = 3,l = 2,m = 1 \cr
& \left( {\text{E}} \right)n = 3,l = 2,m = 0 \cr} $$
A
(D) and (E)
B
(C) and (D)
C
(B) and (C)
D
(A) and (B)
Answer :
(D) and (E)
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Discuss Question
The energy of an orbital is given by $$\left( {n + l} \right).$$
In $$\left( {\text{D}} \right)$$ and $$\left( {\text{E}} \right),\left( {n + l} \right)$$ value is $$(3 + 2) = 5,$$ hence they will have same energy, since here $$n$$ values are also same.
79.
Which of the sequences given below shows the correct increasing order of energy ?
A
$$3s,3p,4s,4p,3d,5s,5p,4d$$
B
$$3s,3p,3d,4s,4p,4d,5s,5p$$
C
$$3s,3p,4s,3d,4p,5s,4d,5p$$
D
$$3s,3p,4s,4p,5s,3d,4d,5p$$
Answer :
$$3s,3p,4s,3d,4p,5s,4d,5p$$
View Solution
Discuss Question
$$3s,3p,4s,3d,4p,5s,4d,5p$$ is the correct order of orbitals with increasing energy.
80.
Rutherford’s scattering experiment is related to the size of the
A
nucleus
B
atom
C
electron
D
neutron
Answer :
nucleus
View Solution
Discuss Question
According to Rutherford's experiment. "The central part consisting of whole of the positive charge and most of the mass, called nucleus, is extremely small in size compared to the size of the atom."