112.
Choose the correct option by arranging the following compounds in increasing order of basicity :
$$C{H_3}N{H_2},{\left( {C{H_3}} \right)_2}NH,N{H_3},$$ $${C_6}{H_5}N{H_2}$$
114.
A dichloroderivative $$(A)$$ on treating with $$KCN$$ followed by acid hydrolysis and heating gives a monobasic acid $$(B)$$ along with liberation of $$C{O_2}.$$ $$(B)$$ on heating with liquid ammonia followed by treating with $$B{r_2}/KOH$$ gives $$(C)$$ which on treating with $$NaN{O_2}$$ and $$HCl$$ at low temperature followed by oxidation gives a monobasic acid $$(D)$$ having molecular mass 74. $$'C'$$ in the whole process would be
The overall reaction can be summarized as follows:
Structure of $$(D)$$ can be :
$$RCOOH = 74,$$
$$\eqalign{
& R = 74 - \left( {COOH} \right) \cr
& \,\,\,\,\,\, = 74 - 45 \cr
& \,\,\,\,\,\, = 29 \cr} $$
i.e., $$R = {C_2}{H_5}$$ and hence acid $$D$$ is $$C{H_3} - C{H_2} - COOH.$$
Now $$(C)$$ will be $$C{H_3} - C{H_2} - C{H_2}N{H_2}$$ which under given conditions gives $$(D)$$ and thus, $$(B)$$ will be butanoic acid which first forms amide. This amide undergoes Hoffmann bromamide reaction to give $$n$$ - propylamine $$(C).$$ To get butanoic acid $$(B)$$ under given conditions dihalide $$(A)$$ will be 1, 1-dichloropropane only. The reactions can be represented as :
115.
Which of the following reactions is not correctly matched?
A
Reaction used to convert amide into primary amine with one carbon atom less - Hoffmann bromamide reaction
B
Reaction used to convert primary amines into isocyanides - Carbylamine reaction
C
Reaction used to distinguish primary, secondary and tertiary amines - Hinsberg's reaction
D
Preparation of primary amines using phthalimide - Victor Meyer's synthesis
Answer :
Preparation of primary amines using phthalimide - Victor Meyer's synthesis
$${1^ \circ }$$ Nitroalkanes on hydrolysis with boiling $$85\% \,{H_2}S{O_4}$$ give acids.
\[C{{H}_{3}}C{{H}_{2}}N{{O}_{2}}+{{H}_{2}}O+{{H}_{2}}S{{O}_{4}}\xrightarrow{\text{heat}}C{{H}_{3}}COOH+{{\left[ N{{H}_{3}}OH \right]}^{+}}HSO_{4}^{-}\]
118.
Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute $$HCl.$$ The compound so formed is converted into tetrafluoroborate which is subsequently heated dry. The final product is
No explanation is given for this question. Let's discuss the answer together.
120.
Aniline in a set of reactions yielded a product \[\xrightarrow[HCl]{NaN{{O}_{2}}}A\xrightarrow{CuCN}B\xrightarrow[Ni]{{{H}_{2}}}\] \[C\xrightarrow{HN{{O}_{2}}}D\]
The structure of the product $$D$$ would be