Canizzaro’s reaction is a disproportionation reaction of aldehyde in which one molecule of aldehyde is reduced to alcohol whereas other is oxidised to salt of carboxylic acid
\[{{C}_{6}}{{H}_{5}}CHO+KOH\to {{C}_{6}}{{H}_{5}}C{{H}_{2}}OH+{{C}_{6}}{{H}_{5}}COOK\]
32.
The major product of the following reaction sequence is
The carbonyl group is highly reactive polar group. It is polarised due to the higher
electronegativity of oxygen in comparison to carbon. As a result, the electrons present between carbon and oxygen are more attracted towards oxygen atom. The actual structure may be represented as
Consequently, the carbonyl carbon is positively charged while the oxygen is negatively charged. The positively charged carbon is easily attacked by a nucleophilic reagent $$\left( {N{u^ - }} \right).$$
$$s{p^2}$$ hybridisation planar structure.
$$s{p^3}$$ hybridisation tetrahedral structure.
36.
Identify the final product. \[\xrightarrow[HCl,\,\Delta ]{Zn\left( Hg \right)}\]
38.
\[\underset{\left( A \right)}{\mathop{{{C}_{16}}{{H}_{16}}}}\,\xrightarrow{{{O}_{3}}}\underset{{{C}_{8}}{{H}_{8}}O}{\mathop{\left( B \right)}}\,\xrightarrow[H{{O}^{-}}/\Delta ]{N{{H}_{2}}-N{{H}_{2}}}\]
reactant $$(A)$$ in this reaction is :