By oxidation of tertiary alcohol with stronger oxidising agents, ketones may be formed along with carboxylic acid.
122.
Identify $$(X), (Y)$$ and $$(Z)$$ in the given reaction sequence.
\[C{{H}_{3}}COC{{H}_{3}}\xrightarrow[\text{heat}]{{{I}_{2}}+NaOH}X\] \[\xrightarrow[\text{heat}]{Ag}Y\xrightarrow[\text{heat}]{\frac{{{H}_{2}}S{{O}_{4}}}{HgS{{O}_{4}}}}Z\]
124.
Identify $$Z$$ in the following reaction sequence.
\[C{{H}_{3}}CHO\xrightarrow[Dil.\,{{H}_{2}}S{{O}_{4}}]{MnO_{4}^{-}}X\xrightarrow{SOC{{l}_{2}}}\] \[Y\xrightarrow[\Delta ]{C{{H}_{3}}COONa}Z\]
125.
A carbonyl compound reacts with hydrogen cyanide to form cyanohydrin which on
hydrolysis forms a racemic mixture of $$\alpha $$ - hydroxy acid. The carbonyl compound is
In this reaction, by the complete hydrolysis of cyanide gives acid and partial hydrolysis gives amide.
If it is racemic mixture, therefore such $$C$$ - atom must be asymmertic carbon atom.
126.
Reaction by which benzaldehyde cannot be prepared ?
A$$ + Cr{O_2}C{l_2}$$ and $$C{S_2}$$ followed by $${H_3}{O^ + }$$
B$$ + {H_2}$$ in presence of $$Pd{\text{ - }}BaS{O_4}$$
C$$ + CO + HCl$$ in presence of $$anhy.$$ $$AlC{l_3}$$
This reaction is known as Etard reaction.
This reaction is called Rosenmund reaction.
The above reaction is known as Gattermann-Koch aldehyde synthesis.
Thus, from the reactants given in option (D) benzaldehyde is not obtained.
127.
The product formed in aldol condensation is
A
a beta-hydroxy acid
B
a beta-hydroxy aldehyde or a beta-hydroxy ketone
C
an alpha-hydroxy aldehyde or ketone
D
an alpha, beta unsaturated ester
Answer :
a beta-hydroxy aldehyde or a beta-hydroxy ketone
Condensation between two molecules of an aldehyde or a ketone having atleast one $$\alpha $$ - hydrogen atom in presence of a base to form a $$\beta $$ - hydroxy aldehyde or $$\beta $$ - hydroxy ketone is known as aldol condensation. Aldol condensation are divided into two parts one is self aldol condensation and another is cross-aldol condensation, when both molecules are same then it is called self aldol and vice versa.
128.
Match the reagents in column I with products formed by reactions with acetone in column II and mark the appropriate choice.
In $$C{H_2} = CH - CHO$$ due to $$-M$$ - effect of $$-CHO$$ group, polarisation of electron takes place as follows :
Hence, partial polarisation is represented as
$$\mathop {C{H_2}}\limits^{\delta + } = CH - CH = \mathop O\limits^{\delta - } $$
130.
The correct set of reagents to carry out the following conversion
A
$${B_2}{H_6}/{\text{diglyme}},{H_2}{O_2}/NaOH,PCC/C{H_2}C{l_2}$$