\[Sn+\underset{\text{Steam}}{\mathop{2{{H}_{2}}O}}\,\xrightarrow{\Delta }Sn{{O}_{2}}+2{{H}_{2}}\]
Tin decomposes steam to form tin dioxide and dihydrogen gas.
152.
Out of $$\left( {\text{i}} \right)Xe{O_3}\left( {{\text{ii}}} \right)XeO{F_4}$$ and $$\left( {{\text{iii}}} \right)Xe{F_6},$$ the molecules having same number of lone pairs on $$Xe$$ are
The correct order of ionisation enthalpies is
$$F > P > S > B$$
NOTE : On moving along a period ionization enthalapy increases from left to right and decreases from top to bottom in a group. But this trend breaks up in case of atom having fully or half filled stable orbitals.
In this case $$P$$ has a stable half filled electronic configuration hence its ionisation enthalapy is greater in comparision to $$S$$ . Hence the correct order is $$B < S < P < F.$$
155.
First ionisation enthalpy of $$Al$$ is lower than that of $$Mg.$$ This is because
A
the size of $$Al$$ is bigger than $$Mg$$
B
ionisation enthalpy decrease in a period from left to right
C
it is easier to remove electron from unpaired $$3{p^1}$$ than from paired $$3{s^2}$$
D
aluminium is a passive metal while magnesium is active metal
Answer :
it is easier to remove electron from unpaired $$3{p^1}$$ than from paired $$3{s^2}$$
Electronic configuration of $$Al - 1{s^2}2{s^2}2{p^6}3{s^2}3{p^1}$$
Electronic configuration of $$Mg - 1{s^2}2{s^2}2{p^6}3{s^2}$$
It is difficult to remove electron from paired $$3{s^2}$$ - orbital than unpaired $$3{p^1}.$$ Hence, $$I.E.$$ of $$Al$$ is lower than $$Mg.$$
156.
Match the column I with column II and mark the appropriate choice.
$$P{H_5}$$ does not exist due to very less electronegativity difference between $$P$$ and $$H.$$
Hydrogen is slightly more electronegative than phosphorus, thus could not hold significantly the sharing electrons.
On the other hand, $$BiC{l_5}$$ does not exist due to inert pair effect.
On moving down the group, +5 oxidation state becomes less stable while +3 oxidation state becomes more stable.
In $$S{O_2},p\pi - d\pi $$ and $$p\pi - p\pi $$ both types of bonds are present
Thus, $$Se{F_4}$$ and $$C{H_4}$$ do not have same shape.
Thus, option (C) is incorrect statement.
158.
Which one of the following compounds is not a protonic acid?
$$B{\left( {OH} \right)_3}$$ is not a protonic acid because it does not give proton on ionisation directly, while it acts as Lewis acid due to acceptance of $$O{H^ - }$$ from water and forms a hydrated species.
$$B{\left( {OH} \right)_3} + {H_2}O \to {\left[ {B{{\left( {OH} \right)}_4}} \right]^ - } + {H^ + }$$
159.
Nitrogen is used to fill electric bulbs because