When $$C{O_2}$$ is bubbled through a cold solution of barium peroxide in water, $${H_2}{O_2}$$ is obtained.
$$Ba{O_2} + C{O_2} + {H_2}O \to $$ $$BaC{O_3} \downarrow + {H_2}{O_2}$$
42.
Which physical property of dihydrogen is wrong ?
No explanation is given for this question. Let's discuss the answer together.
47.
Which of the following reactions is an example of use of water gas in the synthesis of other compounds?
A
\[C{{H}_{4\left( g \right)}}+{{H}_{2}}{{O}_{\left( g \right)}}\xrightarrow[Ni]{1270\,K}C{{O}_{\left( g \right)}}+{{H}_{2\left( g \right)}}\]
B
\[C{{O}_{\left( g \right)}}+{{H}_{2}}{{O}_{\left( g \right)}}\xrightarrow[\text{Catalyst}]{673\,K}C{{O}_{2\left( g \right)}}+{{H}_{2\left( g \right)}}\]
C
\[{{C}_{n}}{{H}_{2n+2}}+n{{H}_{2}}{{O}_{\left( g \right)}}\xrightarrow[Ni]{1270\,K}\] \[nCO+\left( 2n+1 \right){{H}_{2}}\]
D
\[C{{O}_{\left( g \right)}}+2{{H}_{2\left( g \right)}}\xrightarrow[\text{Catalyst}]{\text{Cobalt}}C{{H}_{3}}O{{H}_{\left( l \right)}}\]
Answer :
\[C{{O}_{\left( g \right)}}+2{{H}_{2\left( g \right)}}\xrightarrow[\text{Catalyst}]{\text{Cobalt}}C{{H}_{3}}O{{H}_{\left( l \right)}}\]
The mixture of $$CO$$ and $${H_2}$$ is called water gas. As this mixture of $$CO$$ and $${H_2}$$ is used for the synthesis of methanol and a number of hydrocarbons, it is also called 'synthesis gas' or 'syngas'.
48.
What is the trend of boiling points of hydrides of $$N,O$$ and $$F?$$
A
Due to lower molecular masses $$N{H_3},{H_2}O$$ and $$HF$$ have lower boiling points than those of the subsequent group member hydrides.
B
Due to higher electronegativity of $$N, O$$ and $$F;N{H_3},{H_2}O$$ and $$HF$$ show hydrogen bonding and hence higher boiling points than the hydrides of their subsequent group members.
C
There is no regular trend in the boiling points of hydrides.
D
Due to higher oxidation states of $$N, O$$ and $$F,$$ the boiling points of $$N{H_3},{H_2}O$$ and $$HF$$ are higher than the hydrides of their subsequent group members.
Answer :
Due to higher electronegativity of $$N, O$$ and $$F;N{H_3},{H_2}O$$ and $$HF$$ show hydrogen bonding and hence higher boiling points than the hydrides of their subsequent group members.
Due to higher electronegativity, the extent of hydrogen bonding is quite appreciable.
49.
Given below are two reactions of water with sodium and carbon dioxide. What is the nature of water in these reactions?
$$\left( {\text{i}} \right)2Na + 2{H_2}O \to 2NaOH + {H_2}$$
$$\left( {{\text{ii}}} \right)6C{O_2} + 12{H_2}O \to $$ $${C_6}{H_{12}}{O_6} + 6{H_2}O + 6{O_2}$$
A
In (ii) water acts as an oxidising agent and in (i) it acts as a reducing agent.
B
In (i) water acts as an oxidising agent while in (ii) it acts as a reducing agent.
C
In both (i) and (ii), hydrogen acts as a reducing agent.
D
In both (i) and (ii), hydrogen acts as an oxidising agent.
Answer :
In (i) water acts as an oxidising agent while in (ii) it acts as a reducing agent.
With sodium metal water acts as an oxidising agent and gets reduced to $${H_2},$$ with $$C{O_2}$$ water acts as a reducing agent and is oxidised to oxygen.
50.
Choose the correct statement about the given figures.
A
(II) represents solid state while (III) represents liquid state.
B
(II) represents liquid state while (III) represents solid state.
C
(I) represents solid state while (III) represents liquid state.
D
(I) represents liquid state while (III) represents solid state.
Answer :
(II) represents liquid state while (III) represents solid state.