The complex salt of metaphosphoric acid, sodium hexametaphosphate $${\left( {NaP{O_3}} \right)_6}$$ is known as calgon. It is represented as $$N{a_2}\left[ {N{a_4}{{\left( {P{O_3}} \right)}_6}} \right].$$
113.
$$2\,g$$ of aluminium is treated separately with excess of dilute $${H_2}S{O_4}$$ and excess of $$NaOH.$$ The ratio of the volumes of hydrogen evolved is
115.
The hydride ion $${H^ - }$$ is a stronger base than hydroxide ion $$O{H^ - }.$$ Which of the following reactions will occur if sodium hydride $$\left( {NaH} \right)$$ is dissolved in water?
A
$$H_{\left( {aq} \right)}^ - + {H_2}{O_{\left( l \right)}} \to {H_3}O_{\left( {aq} \right)}^ - $$
B
$$H_{\left( {aq} \right)}^ - + {H_2}{O_{\left( l \right)}} \to OH_{\left( {aq} \right)}^ - + {H_{2\left( g \right)}}$$
C
$$H_{\left( {aq} \right)}^ - + {H_2}{O_{\left( l \right)}} \to {\text{no reaction}}$$
D
$${\text{None of these}}$$
Answer :
$$H_{\left( {aq} \right)}^ - + {H_2}{O_{\left( l \right)}} \to OH_{\left( {aq} \right)}^ - + {H_{2\left( g \right)}}$$
$${H_2}{O_2}$$ is obtained by the electrolysis of a cold 50% solution of $${H_2}S{O_4}.$$
$$2{H_2}S{O_4} \to 2{H^ + } + 2HSO_4^ - $$
\[\underset{\,\,\,\,\,\,\,\,2HSO_{4\left( aq \right)}^{-}+2H_{\left( aq \right)}^{+}+{{H}_{2}}{{O}_{2\left( aq \right)}}}{\mathop{2HSO_{4}^{-}\xrightarrow{\text{Electrolysis}}\underset{\begin{smallmatrix}
\text{Peroxodisulphate} \\
\downarrow \,\text{Hydrolysis}
\end{smallmatrix}}{\mathop{H{{O}_{3}}SOOS{{O}_{3}}{{H}_{\left( aq \right)}}}}\,}}\,\]
119.
In context with the industrial preparation of hydrogen from water gas $$\left( {CO + {H_2}} \right),$$ which of the following is the correct statement?
A
$$CO\,and\,{H_2},$$ are fractionally separated using differences in their densities
B
$$CO$$ is removed by absorption in aqueous $$C{u_2}C{I_2}$$ solution
C
$${H_2}\,$$ is removed through occlusion with $$pd$$
D
$$CO$$ is oxidised to $$C{O_2}$$ with steam in the presence of a catalyst followed by absorption of of $$C{O_2}$$ in alkali
Answer :
$$CO$$ is oxidised to $$C{O_2}$$ with steam in the presence of a catalyst followed by absorption of of $$C{O_2}$$ in alkali
On the industrial scale hydrogen is prepared from water gas according to following reaction sequence
\[\underbrace{CO+{{H}_{2}}}_{\text{water gas }}+\underbrace{{{H}_{2}}O}_{\text{(steam) }}\xrightarrow{\text{catalyst}}C{{O}_{2}}+2{{H}_{2}}\] \[\xrightarrow[\left( \text{alkali} \right)]{2NaOH}N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O\]
From the above it is clear that $$CO$$ is first oxidised to $$C{O_2}$$ which is then absorbed in $$NaOH.$$
120.
The reaction of $${H_2}{O_2}$$ with sulphur is an example of ........ reaction
In this reaction $${H_2}S$$ is oxidised to sulphur and $${H_2}{O_2}$$ is reduced to $${H_2}O,$$ hence this reaction show oxidation-reduction both i.e., redox reaction.