$$C{H_3}Br + N{u^ - } \to C{H_3} - Nu + B{r^ - }$$ The decreasing order of the rate of the above reaction with nucleophiles $$\left( {N{u^ - }} \right)$$ A to D is
$$\left[ {N{u^ - } = \left( {\text{A}} \right)Ph{O^ - },\left( {\text{B}} \right)Ac{O^ - },\left( {\text{C}} \right)H{O^ - },\left( {\text{D}} \right)C{H_3}{O^ - }} \right]$$
A.
A > B > C > D
B.
B > D > C > A
C.
D > C > A > B
D.
D > C > B > A
Answer :
D > C > A > B
Solution :
TIPS/Formulae :
The stronger the acid, the weaker the conjugate base formed.
The acid character follows the order :
$$C{H_3}COOH > {C_6}{H_5}OH > {H_2}O > C{H_3}OH$$
The basic character will follow the order
$$C{H_3}CO{O^ - } < {C_6}{H_5}{O^ - } < {O^ - }H < C{H_3}{O^ - }$$
Releted MCQ Question on Organic Chemistry >> General Organic Chemistry
Releted Question 1
The bond order of individual carbon-carbon bonds in
benzene is