Question
Bond angle in $${H_2}O\left( {{{104.5}^ \circ }} \right)$$ is higher than the bond angle of $${H_2}S\left( {{{92.1}^ \circ }} \right).$$ The difference is due to
Bond angle in $${H_2}O\left( {{{104.5}^ \circ }} \right)$$ is higher than the bond angle of $${H_2}S\left( {{{92.1}^ \circ }} \right).$$ The difference is due to
A.
$$O$$ is diatomic and $$S$$ is tetra-atomic
B.
difference in electronegativity of $$S$$ and $$O$$
C.
difference in oxidation states of $$S$$ and $$O$$
D.
difference in shapes of hybrid orbitals of $$S$$ and $$O.$$
Answer :
difference in electronegativity of $$S$$ and $$O$$