Question

Benzoic acid gives benzene on being heated with $$X$$ and phenol gives benzene on being heated with $$Y.$$ Therefore, $$X$$ and $$Y$$ are respectively

A. sodalime and copper
B. $$Zn$$  dust and $$NaOH$$
C. $$Zn$$  dust and sodalime
D. sodalime and zinc dust  
Answer :   sodalime and zinc dust
Solution :
Carboxylic Acid mcq solution image
$$\eqalign{ & {\text{Here}}\,\,x = NaOH + CaO\,{\text{(soda line)}} \cr & y = Zn\,\,{\text{dust}} \cr} $$

Releted MCQ Question on
Organic Chemistry >> Carboxylic Acid

Releted Question 1

When acetaldehyde is heated with Fehling’s solution it gives a precipitate of

A. $$Cu$$
B. $$CuO$$
C. $$C{u_2}O$$
D. $$Cu + C{u_2}O + CuO$$
Releted Question 2

In the Cannizzaro reaction given below,
\[2PhCHO\xrightarrow{^{-}OH}PhC{{H}_{2}}OH+PhCO_{2}^{-},\]
the slowest step is

A. the attack of $$^ - OH$$  at the carbonyl group,
B. the transfer of hydride to the carbonyl group,
C. the abstraction of proton from the carboxylic acid,
D. the deprotonation of $$PhC{H_2}OH.$$
Releted Question 3

When propionic acid is treated with aqueous sodium bicarbonate, $$C{O_2}$$  is liberated. The $$'C'$$ of $$C{O_2}$$  comes from

A. methyl group
B. carboxylic acid group
C. methylene group
D. bicarbonate
Releted Question 4

Benzoyl chloride is prepared from benzoic acid by

A. $$C{l_2},hv$$
B. $$S{O_2}C{l_2}$$
C. $$SOC{l_2}$$
D. $$C{l_2},{H_2}O$$

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