As a result of change in the magnetic flux linked to the closed loop shown in the figure, an emf $$V$$ volt is induced in the loop. The work done (joule) in taking a charge $$q$$ coulomb once along the loop is
A.
$$qV$$
B.
zero
C.
$$2\,qV$$
D.
$$\frac{{qV}}{2}$$
Answer :
$$qV$$
Solution :
Work done in moving a charge through potential difference $$V$$ is given by $$W = qV$$
Releted MCQ Question on Electrostatics and Magnetism >> Electromagnetic Induction
Releted Question 1
A thin circular ring of area $$A$$ is held perpendicular to a
uniform magnetic field of induction $$B.$$ $$A$$ small cut is made in the ring and a galvanometer is connected across the ends such that the total resistance of the circuit is $$R.$$ When the ring is suddenly squeezed to zero area, the charge flowing through the galvanometer is
A thin semi-circular conducting ring of radius $$R$$ is falling with its plane vertical in horizontal magnetic induction $$\overrightarrow B .$$ At the position $$MNQ$$ the speed of the ring is $$v,$$ and the potential difference developed across the ring is
A.
zero
B.
$$\frac{{Bv\pi {R^2}}}{2}$$ and $$M$$ is at higher potential
Two identical circular loops of metal wire are lying on a table without touching each other. Loop-$$A$$ carries a current which increases with time. In response, the loop-$$B$$
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