Question
Arrange the following ions in the order of decreasing $$X – O$$ bond length, where $$X$$ is the central atom
A.
$$ClO_4^ - ,SO_4^{2 - },PO_4^{3 - },SiO_4^ - $$
B.
$$SiO_4^{4 - },PO_4^{3 - },SO_4^{2 - },ClO_4^ - $$
C.
$$SiO_4^{4 - },PO_4^{3 - },ClO_4^ - ,SO_4^{2 - }$$
D.
$$SiO_4^{4 - },SO_4^{2 - },PO_4^{3 - },ClO_4^ - $$
Answer :
$$SiO_4^{4 - },PO_4^{3 - },SO_4^{2 - },ClO_4^ - $$
Solution :
More will be the electronegativity of $$X,$$ lesser will be the bond length of $$X-O$$ bond.