Question
Amongst $${H_2}O,{H_2}S,{H_2}Se\,\,{\text{and}}\,\,{H_2}Te,$$ the one with the highest boiling point is
A.
$${H_2}O$$ because of hydrogen bonding
B.
$$\,{H_2}Te$$ because of higher molecular weight
C.
$${H_2}S$$ because of hydrogen bonding
D.
$${H_2}Se$$ because of lower molecular weight
Answer :
$${H_2}O$$ because of hydrogen bonding
Solution :
TIPS/Formulae :
(i) Hydrogen bonding increases the boiling point.
(ii) Hydrogen bonds are formed in compounds having $$F$$ or $$O$$ or $$N$$ with hydrogen
$$S,\,\,Se,\,\,Te$$ cannot undergo hydrogen bond formation
because of their larger size and lower electronegativity values.