Question
Allyl isocyanide has
A.
$$9\,\sigma \,\,{\text{and}}\,\,4\,\pi {\text{ - bonds}}$$
B.
$$8\,\sigma \,\,{\text{and}}\,\,5\,\pi {\text{ - bonds}}$$
C.
$$9\,\sigma ,3\,\,\pi \,\,{\text{and}}\,\,2\,\,{\text{non - bonded electrons}}$$
D.
$$8\,\sigma ,3\,\pi \,\,{\text{and}}\,\,4\,\,{\text{non - bonded electrons}}$$
Answer :
$$9\,\sigma ,3\,\,\pi \,\,{\text{and}}\,\,2\,\,{\text{non - bonded electrons}}$$
Solution :
Allyl isocyanide has the structure
$${H_2}C = CH - C{H_2} - N\mathop = \limits^ \to C$$
it has $$9\sigma $$ and $$3\pi $$ bonds along with 2 nonbonded electrons