$$Al{F_3}$$ is soluble in $$HF$$ only in presence of $$KF.$$
It is due to the formation of
A.
$${K_3}\left[ {Al{F_3}{H_3}} \right]$$
B.
$${K_3}\left[ {Al{F_6}} \right]$$
C.
$$Al{H_3}$$
D.
$$K\left[ {Al{F_3}H} \right]$$
Answer :
$${K_3}\left[ {Al{F_6}} \right]$$
Solution : Key Idea $$A{l^{3 + }}$$ shows maximum coordination number 6, thus it will form $$AlF_6^{3 - }.$$
$${Al{F_3}}$$ forms $${K_3}\left[ {Al{F_6}} \right]$$ when dissolved in $$HF$$ in the presence of $$KF$$ as shown below :
\[Al{{F}_{3}}+3KF\xrightarrow{HF}{{K}_{3}}\left[ Al{{F}_{6}} \right]\]
Releted MCQ Question on Inorganic Chemistry >> P - Block Elements
Releted Question 1
The reddish brown coloured gas formed when nitric oxide is oxidised by air is