According to molecular orbital theory which of the following statement about the magnetic character and bond order is correct regarding $$O_2^ + $$

Solution :
$${O_2}:\sigma 1{s^2},{\sigma ^*}1{s^2},\sigma 2{s^2},{\sigma ^*}2{s^2},\sigma 2p_x^2,$$      $$\left\{ {_{\pi 2p_z^2}^{\pi 2p_y^2},\left\{ {_{{\pi ^*}2p_z^1}^{{\pi ^*}2p_y^1}} \right.} \right.$$
Bond order $$\, = \frac{{10 - 6}}{2} = 2$$
(two unpaired electrons in antibonding molecular orbital)
$$O_2^ + :\,\sigma 1{s^2},{\sigma ^*}1{s^2},\sigma 2{s^2},\sigma 2p_x^2,$$     $$\left\{ {_{\pi 2p_z^2}^{\pi 2p_y^2},\left\{ {_{{\pi ^*}2p_z^0}^{{\pi ^*}2p_y^1}} \right.} \right.$$
Bond order $$ = \frac{{10 - 5}}{2} = 2.5$$
(One unpaired electron in antibonding molecular orbital)
Hence $${O_2}$$ as well as $$O_2^ + $$ is paramagnetic, and bond order of $$O_2^ + $$  is greater than that of $${O_2}.$$