According to Bohr's theory, the angular momentum of an electron in 5th orbit is
A.
$$10\frac{h}{\pi }\,$$
B.
$$2.5\frac{h}{\pi }$$
C.
$$25\frac{h}{\pi }$$
D.
$$1.0\frac{h}{\pi }$$
Answer :
$$2.5\frac{h}{\pi }$$
Solution :
Angular momentum of an electron in nth orbital is given by,
$$\eqalign{
& mvr = \frac{{nh}}{{2\pi }} \cr
& {\text{For}}\,n = 5,\,{\text{we}}\,{\text{have}} \cr
& {\text{Angular momentum of electron}} \cr
& = \frac{{5h}}{{2\pi }} = \frac{{2.5h}}{\pi } \cr} $$
Releted MCQ Question on Physical Chemistry >> Atomic Structure
Releted Question 1
The number of neutrons in dipositive zinc ion with mass number 70 is