A train of $$150\,m$$ length is going towards north direction at a speed of $$10\,m{s^{ - 1}}.$$ A parrot flies at a speed of $$5\,m{s^{ - 1}}$$ towards south direction parallel to the railway track. The time taken by the parrot to cross the train is equal to
A.
$$12\,s$$
B.
$$8\,s$$
C.
$$15\,s$$
D.
$$10\,s$$
Answer :
$$10\,s$$
Solution :
So by figure the velocity of parrot w.r.t. train is $$ = 5 - \left( { - 10} \right) = 15\,m/\sec $$
so time taken to cross the train is $$ = \frac{{{\text{length of train}}}}{{{\text{relative velocity}}}} = \frac{{150}}{{15}} = 10\,\sec $$
Releted MCQ Question on Basic Physics >> Kinematics
Releted Question 1
A river is flowing from west to east at a speed of $$5$$ metres per minute. A man on the south bank of the river, capable of swimming at $$10$$ metres per minute in still water, wants to swim across the river in the shortest time. He should swim in a direction-
A boat which has a speed of $$5 km/hr$$ in still water crosses a river of width $$1 \,km$$ along the shortest possible path in $$15 \,minutes.$$ The velocity of the river water in $$km/hr$$ is-
In $$1.0\,s,$$ a particle goes from point $$A$$ to point $$B,$$ moving in a semicircle of radius $$1.0 \,m$$ (see Figure). The magnitude of the average velocity-
A ball is dropped vertically from a height $$d$$ above the ground. It hits the ground and bounces up vertically to a height $$\frac{d}{2}.$$ Neglecting subsequent motion and air resistance, its velocity $$v$$ varies with the height $$h$$ above the ground as-