Question
A thermodynamic system undergoes cyclic process $$ABCDA$$ as shown in figure. The work done by the system in the cycle is
A thermodynamic system undergoes cyclic process $$ABCDA$$ as shown in figure. The work done by the system in the cycle is
A.
$${p_0}{V_0}$$
B.
$$2{p_0}{V_0}$$
C.
$$\frac{{{p_0}{V_0}}}{2}$$
D.
zero
Answer :
zero
Solution :
Work done in the cyclic process = Area bounded by the closed configuration = Area of closed configuration
$$ = \frac{1}{2} \times {V_0} \times {p_0} - \frac{1}{2} \times {V_0} \times {p_0} = 0\left( {{\text{zero}}} \right).$$
Work done in the cyclic process = Area bounded by the closed configuration = Area of closed configuration
$$ = \frac{1}{2} \times {V_0} \times {p_0} - \frac{1}{2} \times {V_0} \times {p_0} = 0\left( {{\text{zero}}} \right).$$
