Question
A thermodynamic system is taken from state $$A$$ to $$B$$ along $$ACB$$ and is brought back to $$A$$ along $$BDA$$ as shown in the $$p-V$$ diagram. The net work done during the complete cycle is given by the area
A thermodynamic system is taken from state $$A$$ to $$B$$ along $$ACB$$ and is brought back to $$A$$ along $$BDA$$ as shown in the $$p-V$$ diagram. The net work done during the complete cycle is given by the area
A.
$${p_1}ACB{p_2}{p_1}$$
B.
$$ACBB'A'A$$
C.
$$ACBDA$$
D.
$$ADBB'A'A$$
Answer :
$$ACBDA$$
Solution :
Work done during path $$ACB = {\text{area}}\,ACBB'A'A$$
Work done during path $$BDA = {\text{area}}\,BDAA'B'B$$
∴ Work done during going from $$ACB$$ and then to $$BDA$$ path is $$ = {\text{area}}\,ACBB'A'A - {\text{area}}\,BDAA'B'B$$
$$ = {\text{area}}\,ACBDA$$
NOTE
Net work done in cyclic process is given by area under the cycle.
Work done during path $$ACB = {\text{area}}\,ACBB'A'A$$
Work done during path $$BDA = {\text{area}}\,BDAA'B'B$$
∴ Work done during going from $$ACB$$ and then to $$BDA$$ path is $$ = {\text{area}}\,ACBB'A'A - {\text{area}}\,BDAA'B'B$$
$$ = {\text{area}}\,ACBDA$$
NOTE
Net work done in cyclic process is given by area under the cycle.
