Question
A ray of light is incident at the glass-water interface at an angle $$i,$$ it emerges finally parallel to the surface of water, then the value of $${\mu _g}$$ would be
A ray of light is incident at the glass-water interface at an angle $$i,$$ it emerges finally parallel to the surface of water, then the value of $${\mu _g}$$ would be
A.
$$\left( {\frac{4}{3}} \right)\sin i$$
B.
$${\frac{1}{{\sin i}}}$$
C.
$${\frac{4}{3}}$$
D.
1
Answer :
$${\frac{1}{{\sin i}}}$$
Solution :
$$\eqalign{ & {\mu _g}\sin i = {\mu _{air}}\sin {90^ \circ } \cr & {m_g} = \frac{1}{{\sin i}} \cr} $$
$$\eqalign{ & {\mu _g}\sin i = {\mu _{air}}\sin {90^ \circ } \cr & {m_g} = \frac{1}{{\sin i}} \cr} $$
