A projectile is thrown at an angle of $${40^ \circ }$$ with the horizontal and its range is $${R_1}.$$ Another projectile is thrown at an angle $${40^ \circ }$$ with the vertical and its range is $${R_2}.$$ What is the relation between $${R_1}$$ and $${R_2}$$ ?
A.
$${R_1} = {R_2}$$
B.
$${R_1} = 2{R_2}$$
C.
$$2{R_1} = {R_2}$$
D.
$${R_1} = \frac{{4{R_2}}}{5}$$
Answer :
$${R_1} = {R_2}$$
Solution :
$$R$$ is same for both $$\theta $$ and $$\left( {{{90}^ \circ } - \theta } \right).$$ If angle w.r.t. vertical is $${40^ \circ }$$ then w.r.t. horizontal direction it will be $${90^ \circ } - {40^ \circ } = {50^ \circ }.$$
Releted MCQ Question on Basic Physics >> Kinematics
Releted Question 1
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