A pole stands vertically inside a triangular park $$ABC.$$ If the angle of elevation of the top of the pole from each corner of the park is same, then the foot of the pole is at the
A.
centroid
B.
circumcentre
C.
incentre
D.
orthocentre
Answer :
centroid
Solution :
The foot of the pole is at the centroid. Because centroid is the point of intersection of medians $$AD, BE$$ and $$CF,$$ which are the lines joining a vertex with the mid point of opposite side.
Releted MCQ Question on Trigonometry >> Properties and Solutons of Triangle
Releted Question 1
If the bisector of the angle $$P$$ of a triangle $$PQR$$ meets $$QR$$ in $$S,$$ then
From the top of a light-house 60 metres high with its base at the sea-level, the angle of depression of a boat is 15°. The distance of the boat from the foot of the light house is
A.
$$\left( {\frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}} \right)60\,{\text{metres}}$$
B.
$$\left( {\frac{{\sqrt 3 + 1}}{{\sqrt 3 - 1}}} \right)60\,{\text{metres}}$$
C.
$${\left( {\frac{{\sqrt 3 + 1}}{{\sqrt 3 - 1}}} \right)^2}{\text{metres}}$$
In a triangle $$ABC,$$ angle $$A$$ is greater than angle $$B.$$ If the measures of angles $$A$$ and $$B$$ satisfy the equation $$3\sin x - 4{\sin ^3}x - k = 0, 0 < k < 1,$$ then the measure of angle $$C$$ is
In a triangle $$ABC,$$ $$\angle B = \frac{\pi }{3}{\text{ and }}\angle C = \frac{\pi }{4}.$$ Let $$D$$ divide $$BC$$ internally in the ratio 1 : 3 then $$\frac{{\sin \angle BAD}}{{\sin \angle CAD}}$$ is equal to