Question

A plane electromagnetic wave of frequency $$50\,MHz$$   travels in free space along the positive $$x$$-direction. At a particular point in space and time, $$\vec E = 6.3\hat j\,V/m.$$    The corresponding magnetic field $${\vec B},$$ at that point will be:

A. $$18.9 \times {10^{ - 8}}$$
B. $$2.1 \times {10^{ - 8}}$$  
C. $$6.3 \times {10^{ - 8}}$$
D. $$18.9 \times {10^8}$$
Answer :   $$2.1 \times {10^{ - 8}}$$
Solution :
As we know,
$$\left| B \right| = \frac{{\left| E \right|}}{C} = \frac{{6.3}}{{3 \times {{10}^8}}} = 2.1 \times {10^{ - 8}}T$$
As $$\vec V \bot \vec E \bot \vec B$$   therefore direction of is in z direction
$$\vec B = 2.1 \times {10^{ - 8}}\hat kT$$

Releted MCQ Question on
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Releted Question 1

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy $$6\,eV$$  fall on it is $$4\,eV.$$  The stopping potential, in volt, is

A. 2
B. 4
C. 6
D. 10
Releted Question 2

Electrons with energy $$80\,keV$$  are incident on the tungsten target of an X-ray tube. $$K$$-shell electrons of tungsten have $$72.5\,keV$$  energy. X-rays emitted by the tube contain only

A. a continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of $$0.155\mathop {\text{A}}\limits^ \circ $$
B. a continuous X-ray spectrum (Bremsstrahlung) with all wavelengths
C. the characteristic X-ray spectrum of tungsten
D. a continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of $$0.155\mathop {\text{A}}\limits^ \circ $$  and the characteristic X-ray spectrum of tungsten.
Releted Question 3

The intensity of X-rays from a Coolidge tube is plotted against wavelength $$\lambda $$ as shown in the figure. The minimum wavelength found is $${\lambda _C}$$ and the wavelength of the $${K_\alpha }$$ line is $${\lambda _K}.$$  As the accelerating voltage is increased
Modern Physics Miscellaneous mcq question image

A. $${\lambda _K} - {\lambda _C}$$   increases
B. $${\lambda _K} - {\lambda _C}$$   decreases
C. $${\lambda _K}$$ increases
D. $${\lambda _K}$$ decreases
Releted Question 4

The potential difference applied to an X-ray tube is $$5k\,V$$  and the current through it is 3.2$$mA.$$  Then the number of electrons striking the target per second is

A. $$2 \times {10^{16}}$$
B. $$5 \times {10^{6}}$$
C. $$1 \times {10^{17}}$$
D. $$4 \times {10^{15}}$$

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