Question
A mixture having $$2\,g$$ of hydrogen and $$32\,g$$ of oxygen occupies how much volume at $$NTP?$$
A.
44.8$$\,L$$
B.
22.4$$\,L$$
C.
11.2$$\,L$$
D.
67.2$$\,L$$
Answer :
44.8$$\,L$$
Solution :
$$2\,g\,\,{\text{of}}\,\,{{\text{H}}_2} = 1\,mole,$$ $$32\,g\,\,{\text{of}}\,\,{O_2} = 1\,mole$$
$${\text{Total volume of }}2{\text{ }}moles{\text{ of}}$$ $${\text{gases at }}NTP$$
$$\eqalign{
& = 2 \times 22.4\,L \cr
& = 44.8\,L \cr} $$