A generator has an e.m.f. of $$440$$ Volt and internal resistance of $$4000\,hm.$$ Its terminals are connected to a load of $$4000\,ohm.$$ The voltage across the load is
A.
220 volt
B.
440 volt
C.
200 volt
D.
400 volt
Answer :
400 volt
Solution :
Total resistance of the circuit $$ = 4000 + 400 = 4400\,W$$
Current flowing $$i = \frac{V}{R} = \frac{{440}}{{4400}} = 0.1\,{\text{amp}}{\text{.}}$$
Voltage across load $$ = Ri = 4000 \times 0.1 = 400\,{\text{volt}}{\text{.}}$$
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