A gas $$X$$ at $$1\,atm$$ is bubbled through a solution containing a mixture of $$1\,M\,{Y^ - }$$ and $$1\,M\,{Z^ - }$$ at $${25^ \circ }C.$$ If the reduction potential of $$Z > Y > X,$$ then
A.
$$Y$$ will oxidise $$X$$ and not $$Z$$
B.
$$Y$$ will oxidise $$Z$$ and not $$X$$
C.
$$Y$$ will oxidise both $$X$$ and $$Z$$
D.
$$Y$$ will reduce both $$X$$ and $$Z.$$
Answer :
$$Y$$ will oxidise $$X$$ and not $$Z$$
Solution :
As reduction potential $$Y$$ is higher than $$X$$ but lower than $$Z$$ thus $$Y$$ will oxidise $$X$$ and not $$Z.$$
Releted MCQ Question on Physical Chemistry >> Electrochemistry
Releted Question 1
The standard reduction potentials at $$298 K$$ for the following half reactions are given against each
$$\eqalign{
& Z{n^{2 + }}\left( {aq} \right) + 2e \rightleftharpoons Zn\left( s \right)\,\,\,\,\,\,\,\,\, - 0.762 \cr
& C{r^{3 + }}\left( {aq} \right) + 2e \rightleftharpoons Cr\left( s \right)\,\,\,\,\,\,\,\,\, - 0.740 \cr
& 2{H^ + }\left( {aq} \right) + 2e \rightleftharpoons {H_2}\left( g \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0.000 \cr
& F{e^{3 + }}\left( {aq} \right) + 2e \rightleftharpoons F{e^{2 + }}\left( {aq} \right)\,\,\,\,\,\,\,\,0.770 \cr} $$
which is the strongest reducing agent ?
A solution containing one mole per litre of each $$Cu{\left( {N{O_3}} \right)_2};AgN{O_3};H{g_2}{\left( {N{O_3}} \right)_2};$$ is being electrolysed by using inert electrodes. The values of standard electrode potentials in volts (reduction potentials) are :
$$\eqalign{
& Ag/A{g^ + } = + 0.80,\,\,2Hg/H{g_2}^{ + + } = + 0.79 \cr
& Cu/C{u^{ + + }} = + 0.34,\,Mg/M{g^{ + + }} = - 2.37 \cr} $$
With increasing voltage, the sequence of deposition of metals on the cathode will be :