A compound of a metal ion $${M^{x + }}\left( {Z = 24} \right)$$ has a spin only magnetic moment of $$\sqrt {15} $$ Bohr Magnetons. The number of unpaired electrons in the compound are
A.
2
B.
4
C.
5
D.
3
Answer :
3
Solution :
Magnetic moment $$\mu = \sqrt {n\left( {n + 2} \right)} $$ where $$n = $$ number of unpaired electrons
$$\eqalign{
& \sqrt {15} = \sqrt {n\left( {n + 2} \right)} \cr
& \therefore \,\,n = 3 \cr} $$
Releted MCQ Question on Inorganic Chemistry >> D and F Block Elements
Releted Question 1
When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volume of hydrogen evolved is