A compound contains atoms of three elements $$A,B$$ and $$C.$$ If the oxidation number of $$A$$ is $$ + 2,$$ $$B$$ is $$ + 5$$ and that of $$C$$ is $$ - 2,$$ the possible formula of the compound is
A.
$${A_2}{\left( {B{C_3}} \right)_2}$$
B.
$${A_3}{\left( {B{C_4}} \right)_2}$$
C.
$${A_3}{\left( {{B_4}C} \right)_2}$$
D.
$$AB{C_2}$$
Answer :
$${A_3}{\left( {B{C_4}} \right)_2}$$
Solution :
In $${A_3}{\left( {B{C_4}} \right)_2}$$
3 × oxidation number of $$A$$ + 2 [ oxidation number of $$B$$ + 4 × [ oxidation number of $$C$$ ] = 0
3 × ( + 2 ) + 2 [ 5 + 4 × ( - 2 ) ] = 0
6 + 2 [ - 3 ] = 0
Releted MCQ Question on Inorganic Chemistry >> Chemical Bonding and Molecular Structure
Releted Question 1
The compound which contains both ionic and covalent bonds is