Question
A charge $$q$$ moves in a region where electric field $$E$$ and magnetic field $$B$$ both exist, then the force on it is
A.
$$q\left( {v \times B} \right)$$
B.
$$qE + q\left( {v \times B} \right)$$
C.
$$qB + q\left( {B \times v} \right)$$
D.
$$qB + q\left( {E \times v} \right)$$
Answer :
$$qE + q\left( {v \times B} \right)$$
Solution :
If $$E$$ is the electric field strength and $$B$$ is the magnetic field strength and $$q$$ is the charge on a particle, then electric force on the charge
$${F_e} = qE$$
and magnetic force on the charge
$${F_m} = q\left( {v \times B} \right)$$
The net force on the charge
$$F = {F_e} + {F_m} = qE + q\left( {v \times B} \right)$$
Alternative
According to Lorentz force if a charged particle is in both electric field $$\left( E \right)$$ and magnetic field $$\left( B \right),$$ force is given by
$$F = q\left[ {E + \left( {v \times B} \right)} \right]$$